WebSep 10, 2024 · As mentioned, it is a list comprehension (covered in DiveIntoPython3, for example). Here are a few points: [x[1] for x in L] Notice the []'s around the line of code. These are what define a list. This tells you that this code returns a list, so it's of the list type. Hence, this technique is called a "list comprehension." L is your original list. WebUse enumerate when you want both the values and indices in a for loop: for index, item in enumerate(my_list): if item.id == 'specific_id': break else: index = - Menu NEWBEDEV Python Javascript Linux Cheat sheet
How To Get Index Values Of Pandas DataFrames - Python Guides
WebList[0] gives you the first list in the list (try out print List[0]). Then, you index into it again to get the items of that list. Then, you index into it again to get the items of that list. Think of it this way: (List1[0])[0] . WebSep 16, 2024 · A list in Python is a collection of elements. The elements in a list can be of any data type: 1. >>> cool_stuff = [17.5, 'penguin', True, {'one': 1, 'two': 2}, []] This list … slow cooker sweet potato
Python - Ways to find indices of value in list - TutorialsPoint
WebOct 13, 2024 · Syntax: numpy.where(condition[, x, y]) Example 1: Get index positions of a given value. Here, we find all the indexes of 3 and the index of the first occurrence of 3, we get an array as output and it shows all the indexes where 3 is present. WebUse Numpy direct array indexing, as in MATLAB, Julia, ... a = [10, 11, 12, 13, 14, 15]; s = [1, 2, 5] ; import numpy as np list (np.array (a) [s]) # [11, 12, 15] Better yet, just stay with Numpy arrays a = np.array ( [10, 11, 12, 13, 14, 15]) a [s] #array ( [11, 12, 15]) Share Improve this answer Follow answered Aug 19, 2015 at 4:30 Dmitri WebNov 26, 2015 · I am trying to get the index of an element in nested lists in python - for example [[a, b, c], [d, e, f], [g,h]] (not all lists are the same size). ... Find a specific value in a large tree of sublists. 0. Finding an element in nested python list and then replacing it. Related. 4271. Finding the index of an item in a list. soft tissue knee injury