Web0.10x = amount of pure acid from the first batch 0.50 (120-x) = 60-0.5x = amount of pure acid from the second batch We want 120 liters of 18% solution. Therefore, we want 0.18*120 = 21.6 liters of pure acid. The two pure acid subtotals 0.10x and 60-0.50x must add to the 21.6 figure. 0.10x + 60-0.50x = 21.6 -0.40x + 60 = 21.6 -0.40x = 21.6-60 WebFind step-by-step Algebra solutions and your answer to the following textbook question: How many kilograms of salt must be added to 12 kg of an 8% salt solution to make a …
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WebA tank contains 1000 liters (L) of a solution consisting of 100 kg of salt dissolved in water. Pure water is pumped into the tank at the rate of 5 L/s, and the mixture - kept uniform by stirring - is pumped out at the same rate. How long will it be until only 10 kg of salt remains in the tank? Using the terminology consistent with pg.49, (0) 100 Web8 aug. 2024 · The figure below illustrates the above process and shows the distinction between unsaturated and saturated. Figure 16.3. 1: When 30.0 g of NaCl is added to 100 mL, it all dissolves, forming an unsaturated solution. When 40.0 g is added, 36.0 g dissolves and 4.0 g remains undissolved, forming a saturated solution. high blood pressure diuretic
How many kg of pure salt must be added to 8 kg of a 30
Web10 okt. 2015 · Let us mix x kg of pure salt. Pure means the concentration is 100%. so the mount of salt in the solution from here will be x kg. Now total solution is 30+x kg. … WebClick here 👆 to get an answer to your question ️ How many kg of pure salt must be added to 25 kg of a 5% solution of salt and water to increase it to a 12% Login Sign Up Web5 apr. 2024 · As given there is 2% salt in 30 kg solution of salt and water. So amount of salt in 30 kg solution is ⇒ 30 k g × 2 100 ⇒ 0.6 k g The amount of pure salt added is x kg. … how far is melbourne fl to port canaveral fl