If the work done in stretching a wire by 1mm

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August undefined, 2024

Web23 nov. 2024 · Now Work done in stretching wire = ½ Load ×Extension. ∴ Work done = ½ × 100 × 4.444 × 10-2. ∴ Work done = 2.222 J. Ans: Work done in stretching wire is 2.222 J. Example – 11: A uniform steel wire of length 3 m and area of cross-section 2 mm² is extended through 3mm. Calculate the energy stored in the wire, if the elastic limit is ... Web2 dagen geleden · ELONGA, Multi-Strand Stretch Cord, Knotting Cord, Clear Color, 5, 25 or 100m, .3mm, .7mm or 1mm, 5, 25 or 100 metres ad vertisement by ArgusCollection Ad vertisement from shop ArgusCollection

Numerical Problems on Stress, Strain, and Young’s Modulus

Web29 apr. 2024 · Given: 3 × 10^ (-3) J of work is done in stretching a wire by 1 mm. To find: Work done in stretching the wire by 3mm. Calculation: Considering the wire to have spring like effect and the spring constant be k , we can say : In the 1st case : In the 2nd case: So final answer is: SEE ALL Advertisement Still have questions? Find more answers WebABOUT CHANNEL- - A.K.Physics Classes is that youtube channel which study the different topic of class 11th,12th,B.Sc. and some other competitive exam like ai... marco mazzucco

If the work done in stretching a wire by 1mm is 2 J, the work

Web23 nov. 2024 · Find the work done in stretching a wire of length 2 m and of sectional area 1 mm² through 1 mm if Young’s modulus of the material ... Radius of wire = 2/2 = 1mm = 1 × 10-3 m, Stretching load = 10 kg = 10 × 9.8 N, Young’s modulus of elasticity = Y = 12 × 10 10 N/m², and Poisson’s ratio = σ = 0.35. To Find: Lateral ... WebIf work done for stretching a wire by 1 mm is 2 J, then the work necessary for stretching another wire of same material, but with double the radius and half the length by 1 mm (in … Web2 mrt. 2014 · Stress • Stress, defined as force per unit area, is a measure of the intensity of the total internal forces acting within a body across imaginary internal surfaces, as a reaction to external applied forces and body forces. It was introduced into the theory of elasticity by Cauchy around 1822. Stress is a concept that is based on the concept ... marco mazzucconi

The figure below shows a stress-strain graph for a copper wire.

WebIf the work done in stretching a wire by 1 mm is 2 J, the work necessary for stretching another wire of same material but with double radius of cross-section and half the length … Web30 mei 2024 · Find an answer to your question A wire 0.5 m long and I sq.mm in cross-section has ... A wire 0.5 m long and I sq.mm in cross-section has Young's modulus 1.24%N/m How much work is done through 1 mm? Answer A. 0.242) B. 0.112) c. 0.124) D. 0.224) See answer Advertisement Advertisement prangarasaniya8 prangarasaniya8 … cst italia societa consortile a.r.lWebThe weight stretches the wire by 1mm. ... The work done in stretching is [AIEEE-2004] F Fl (A) 2Fl (B) Fl (C) (D) 2l 2 10. A bullet fired into a fixed target loses half of its velocity after penetrating 3cm. How much further it will penetrate before coming to rest assuming that it faces constant ... csti stock price

"Web25 jun. 2024 · The work done in stretching a wire by 1mm is 2J. The work necessary for stretching another wire. asked Apr 28, 2024 in Physics by RakeshSharma (73.5k points) elasticity; 0 votes. 1 answer. A strectching force of 1000 newton is applied at one end of a spring balance and an equal stretching force is applied at the other end at the same ... " - If the work done in stretching a wire by 1mm

If the work done in stretching a wire by 1mm

If the work done in strectching a wire by `1mm` is `2J`, then work ...

Web29 nov. 2024 · (a) A wire 4 m ling and 0.3 mm in diameter is stretched by a force of 100 N. If extension in the wire is 0.3 mm, calculate the potential energy stored in the wire. (b) Find the work done in stretching a wire of cross-section 1 mm 2 and length 2 m through 0.1 mm Young's modulus for the material of wire is 2.0 x 10 11 N/m 2. WebWork done in stretching a wire through 1mm is 2 J. Find the amount of work done (in J) in elongating another wire (of same material with half the length and double the radius of …

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Web16 mei 2024 · If the work done in strectching a wire by `1mm` is `2J`, then work necessary for stretching another wire of same ... . (C) `4 J` D. (D) `32 J` LIVE Course for free WebIf a metal wire is 4m long and a force of 5000N causes it to stretch by 1mm, ... Match. Created by. Erica_Wangelin. Terms in this set (15) 0.00025. If a metal wire is 4m long and a force of 5000N causes it to stretch by 1mm, what is the strain? The maximum stress would be no different. ... You are working in the emergency department (ED) ...

WebA metal wire of length 3 meters and diameter 1mm is stretched by a weight of 10 kg . If Young's modulus for its material be 12.5 x 1010N/m2and σ for it equal to 0.26, calculate the lateral compression produced. (g=9.8 m/s2). Solution : … Web28 jun. 2024 · Calculate the work done in stretching a steel wire 100 cm in length and of cross sectional area 0.030 cm 2 when a load of 100 N is slowly applied before the elastic limit is reached. ... Length of wire l = 2.5m. Elongation, e = 1mm = 1×10-3 m. Force, F = 80 N . Young’s modulus of steel, Y = ? Energy stored in the wire, E = ? We have,

Web18 feb. 2024 · Find the work done in stretching a wire of length 2 m and of sectional area 1 mm² through 1 mm if Young’s modulus of the material of the wire is 2 × 10 11 N/m². Given: Area = A = 1 mm² = 1 × 10 –6 m², Length of wire = L = 2m, Extension in wire = l = 1mm = 1 × 10 –3 m, Young’s modulus = Y =2 × 10 11 N/m². Web25 mrt. 2024 · The work done in stretching a wire is given as W = (1/2).F.dl F is the force required dl is the increase in length (which remains same in both cases) So, we can have W1 / W2 = [ (1/2).F1.dl] / [ (1/2).F2.dl] 2J / W2 = F1 / F2 W2 =2 x ( F2/F1) (1) Now we know that the force is given as F = Y.A. (dl/l) here Y is the Young's Modulus

Web1 apr. 2024 · Now coming on the question, we are asked about the work done when a wire is stretched, Formula for the work done is W = 1 2 ×F× Δ l ….. (1) , where F is the force and Δ l is the change in length We are given, Δ l =0.1mm Length (L) = 2m Y=2 × 10 11 N m 2, Y is the young’s modulus (proportionality constant) and Area of cross-section, 10 − 6 m 2

Web10 apr. 2024 · Find many great new & used options and get the best deals for 100m Rainbow Colourful Elastic Cord 1mm Thread Stretch String Craft DIY Jewelry at the best online prices at eBay! ... 100M 1mm Elastic Wire Stretch Thread Jewelry Necklace DIY Beading String Cout. ... Will usually dispatch within 5 working days of receiving cleared ... cst ipi venda simples nacionalWeb26 feb. 2012 · This force stretches the wire through a small elongation x. Let length of wire = L. Force F produce an extension = x. From the figure. Work done on the wire during stretching = Area covered on the x-axis = Average force × extension. Work done, W = Energy stored. ⇒ Energy stored per unit volume in stretching wire = 0.5 × stress × strain marco mccfb100Web28 apr. 2024 · The work done in stretching a wire by 1mm is 2J. The work necessary for stretching another wire of same material but with double the radius of cross-section and … marco mccottryWeb28 apr. 2024 · 3 × 10^(-3) J of work is done in stretching a wire by 1 mm. To find: Work done in stretching the wire by 3mm. Calculation: Considering the wire to have spring … marco mazzullaWebFind the formula for the work done is stretching a wire and apply it to find the elastic energy stored in a wire originally 5metre long and 1mm in diameter, ... marco mcffbWeb29 nov. 2024 · Find the work done in stretching a wire of length 2 m and of sectional area 1 mm² through 1 mm if Young’s modulus of the material of the wire is 2 × 10 11 N/m². Given: Area = A = 1 mm² = 1 × 10 – 6 m², Length of wire = L = 2m, Extension in wire = l = 1mm = 1 × 10 – 3 m, Young’s modulus = Y =2 × 10 11 N/m². cst iran time converterWebAnswered: A spring 40mm long is stretched by the… bartleby. Science Advanced Physics A spring 40mm long is stretched by the acceleration of a force. If 10N force is required to stretch the spring through 1mm, then work done in stretching through 40mm is? a) 84J b) 48J c) 24J d) 8J. A spring 40mm long is stretched by the acceleration of a force. csti trento